If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-18c^2-6c=0
a = -18; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-18)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-18}=\frac{0}{-36} =0 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-18}=\frac{12}{-36} =-1/3 $
| -1(-3y+-7)=7 | | 37-10x=16+11x | | 3x+4.75=21.25 | | 2x+5×=15 | | -4-9b+8+7b=b | | X=114(3x+5) | | 24=8+2l | | 80.9+29.9=t | | (x-22)+(2x-215)+(1/2x+11)=180 | | -4x+5=6x+4 | | -5x-4=-8-3(x-1) | | 6-4w+3w=w | | 2x-16=26 | | 4x-8=4x-9 | | 2(v-12v)=216v | | x^=98 | | 6=-2/3(7x-2 | | 4x^2-x+4-x-7=0 | | 9(-9-x)=-1 | | 45x+56=0 | | 7x+6(2-x)+18=28+3(6+x) | | 82=20x | | 6(j−88)=18 | | 11+n=3+3n= | | 2(2+3)+8x=6(x-1)+3x | | 10t-8=22 | | 10t−8=22 | | -2.3–5x=10–2x | | (2g+12)=-20 | | 8(3w+10)÷3=-5 | | 3y-28=76 | | 4x+5=4+6x |